Area calculations

Calculate the area of a circle

We all know that for a circle, the formula of area = πr2. But why is it?

Now we have a circle as the image shown


Input the amount of pieces:

(bro literally spend 2 hrs to make this)

As the split amount of the circle increasing, the area of reformed shape is getting more and more close to the rectangle.

The width of rectangle is the orginal radius. Because of the cross arrangement sector, the length is half of the circumference.

The formula for circumference is πd, since the circumference is always π times than the diameter (d).

πd divide by 2, then times r is the formula of a circle, simplyfy it:

πd/2*r

=πr*r (since diameter is always 2 times than radius)

=πr2

Infinitely close

Now consider the question, is infinitely close to the rectangle equals to the rectangle?

Here is an example:

∵0.333... = 1/3

0.333... * 3 = 0.999..., 1/3 * 3 = 1

∴1 = 0.999...

∴Infinitely close is an equal.

So the area of a circle is exaclty πr2

"A farmer uses a circular water sprayer to irrigate a square shaped field. The diameter of the watered circles is 20 metres. "

Calculating the unwatered area

Calculating the unwatered area is easy. All you need to do is to subtract the watered area from the total area.

We know that the watered area is made up of four circles which has the diameter of 20. So the total area as a square is 20 * 20.

Evaluate it. w2 - 4πr2

=(20 * 2)2 - 4 * π * (20 / 2)2

=1600-400π

π to the 2nd decimal

=344

Calculating the central shading area

There are multiple ways to evaluate the area of the central shading area.

1st way: only leave the central 1/4 of the pattern, then evaluate.

We can get rid of the outer graph that is necessary as the graph at right shown

As you can see, we have 4 of the 90 degress sector with a radius of 10 meters as the watered area, the whole field has the side length of 20 meters

Now we can evaluate it.

202 - 4 * 1/4 * π * 102

=400 - 100π

π to the 2nd decimal

=86

2nd way: calculate all of the unwatered area, then divide.

Look at the graph at the right. You can find the unwatered area can be equally split to 16 pieces of the same shape, and there are total 4 of them in the center.

We we need to do now is to subtract the watered area from the total area to get the unwatered area, then divide by 16 and times 4.

[(20 * 2)2 - 4 * π * (20 / 2)2] / 16 * 4

=400-100π

π to the 2nd decimal

=86

Calculating the new central water spiller

Evaluate the center watered circle that is the maximum size but not inheriting others is still easy.

As the image shown on the right, all you need to do is get the diagonal length and subtract those two radius.

The base side length is 20 meters, so the diagonal length is √(202 + 202)

≈28.28 meters

Reduce the radius of the original circle, you can get the new diameter.

28.28 - (10 + 10) = 8.28 meters

We can get the area with the diameter

πr2

=π(8.28/2)2

=17.9776π

π to the 2nd decimal

=56.449664

Extension questions

Is the watered area over 80% of the total field?

Original area:

π * 102 * 4 + 56

π to the 2nd decimal

1312/1600=82%

82%>80% ∴yes


What is the radius of the circle if you want to spill all the field using 4 spiller?

Solve for the diagonal length:

√(20+20)2 * 2

≈56.57

56.57 / 2 / 2 = 14.1425

Math Problem of Water Sprayer

Mathematics 9: Problem Index 2

Coby Qiu

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